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**exampundit**. Here is a set of Quantitative Aptitude Quiz for Upcoming IBPS Exams.

(1) The Cost Price of two car is same. One is sold at a profit of 20% and other for Rs 360 more than the first one. If the overall profit earned after selling the Car is 22%, then what is Cost Price of each car ?

A) 10,00,000.

B) 15,00,000.

C) 9,00,000.

D) Cannot be determined.

E) None of These

(2) Total number of questions in a exam is n. Mr. Sigmund gives right answer of 20 out 25 questions in first part. In second part he gives 60% right answer. In this way he scored 66.67% marks in exam.

If marks allotted to each question is equal and no negative marking is allowed. then total number of questions = ??

A) 85.

B) 75.

C) 90.

D) 50.

E) None of these

(3) A man sells two cycles for 32000 each one at a loss of 20% and other at a gain of 33.33% what is his overall gain/loss ?

A) 20% profit.

B) 16% loss.

B) 4% loss.

D) no profit no loss.

E) None of these

(4) One house and one shop is being sold by a merchant. S.P of each is 1 lakh and on house he got 20% loss and on shop 20% profit. What is overall profit/loss in whole transaction ?

A) 1/12 lakh loss.

B) 3/14 lakh profit.

C) 12.5 lakh loss.

D) 10 lakh profit.

E) None of these

(5) A dealer marks up price of oil by 20% uses faulty weigh of 900 gm in place of 1000 gm and gives a discount of 40% to his customer what is his loss percentage ?

A) 20%.

B) 35%.

C) 25%.

D) 28%.

E) None of these

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(6) Ram used a 140 cm instead of 1 mtr tape while buying clothe. While selling he used to 80 cm tape instead of 1 mtr tape. If he offers 20% discount while selling. What is his overall percentage gain?

A) 40%.

B) 35%.

C) 25%.

D) 60%.

E) None of these

(7) The price of petrol increse from Rs 140/ltr to Rs 180/ltr by what % should cut down on his petrol consumption. If he can afford to to increase his expenditure on petrol by just 9.09% ?

A) 5.88%

B) 5.76%

C) 5.26%.

D) 3.79%.

E) None of these

(8)A, B and C can do a work in 24, 30 and 40 days respectively. If they work such that A works for 1 day, then B for 2 days, then C for 3 days. Then again A for 1 day and so on. How many day will it take to complete the work ?

A) 31.75 days.

B)32.25 days.

C) 32.33 days.

D)32.67 days.

E) None of these

### Answers:

Solutions :-- C
- D
- D
- A
- A
- A
- E
- B

1) 9,00,000

Average % profit = 22

So, total % profit = 22×2 = 44%

44 - 40 = 4% (40 arrived after 20×2)

4% = 360

100% = 9,00,000

2) 75

20/25 = 4/5 = 80% (ri8 in first part)

80% 60%

66.67%

20/3 40/3

1:2

1= 25

So, 3 = 75 and.

3) no profit no loss

Two case occurred here one is loss of 20% and other is profit of 33.33%.

( I try to solve this by reciprocal method which is also useful in further questions)

Case 1) Loss 20%

So it sold at 4/5

Case 2) profit 33.33%

So it sold at 4/3

In this type of questions S.P is supposed to L.C.M of numenator of both reciprocal...

So, in Case1)

S.P = 4

C.P= 4*5/4 = 5

Similarly in case 2)

S.P = 4

C.P = 4*3/4= 3

Total S.P = 4+4 = 8

Total C.P = 5+3= 8

So no profit no loss.

(It looks long in explanation but believe me it's very short and conceptual way to get right answer quickly. It's not trick. It's concept.)

4) 1/12 lakh loss

same as question no 3

Case 1)

Loss 20%

It sold at 4/5

Case 2)

Profit 20%

It sold at 6/5

S.P in case (1) = 12 (LCM of both numenator)

C.P = 12*5/4 = 15

S.P in case (2) = 12

C.P = 12*5/6 = 10

Total S.P = 24

C.P = 25

When each S.P is 12, loss is Rs 1

So when each S.P is 1 lakh, loss is 1/12 lakh

5) 20% loss

In this types of questions always remember SP/CP.

120/100 ( he tried to get 20% profit while buying)

1000/900 ( he used to 900gm instead of 1000gm it means he paid C.P of 900gm but take money of 1000gm)

60/100 ( he gave 40% discount)

Multiply all three to get final reciprocal which is 4/5.

It means loss of 1/5 = 20%

6) 40% profit

Same rule as question no 5

SP/CP =

140/100

*100/80

*80/100

= 7/5

Profit % = 2/5= 40 %

7) none of these

Expenditure = price × Consumption

12/11 = 180/140 * X

X = 28/33

It means reduction = 5/33%

8) 32.25 days

Total work is 120 unit ( LCM of 24, 30 and 40)

A = 24 days ( 5 unit@day) works for 1 day = 5 unit

B = 30 days ( 4 unit@day) works for 2 days = 8 unit

C = 40 days ( 3 unit@day) works for 3 days = 9 unit

6 days = 22 units

5×6days = 22×5 units

30 days = 110 units

31st day = 115 units ( 5 units by A)

32nd day =119 units ( 4 units by B)

Remaining 1 unit will being done by B in 1/4 day

So total day is 32.25 days.

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