SBI PO Prelims 2017: Puzzle Quiz - Set 17 - Exam Pundit - IBPS PO | Clerk | SBI PO | Insurance Exams | SSC Exams | Current Affairs

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Wednesday, March 29, 2017

SBI PO Prelims 2017: Puzzle Quiz - Set 17




Hello and welcome to exampundit. Here is a set of Puzzle Quiz for SBI PO Prelims 2017.

Questions 1 to 3:

Four friends are sitting at the four sides of a square table at a Café. Eighteen cookies and many sachets of sugar, all of equal size, are kept at the table. The one opposite Sam has black coffee with twice as many sachets of sugar as him and three cookies more than him. Joe has half as many sachets of sugar but twice as many cookies as the one opposite him. Sam has the same number of cookies as one of his friends. Raman has more sugar in his coffee than Arun and also adds milk to it. No one uses a sachet partially or has more than four sachets.

1. How does Arun have his coffee?
1) Black, with 1 sachet of sugar
2) With milk and 3 sachets of sugar
3) Black, with 2 sachets of sugar
4) Cannot be determined


2. Which of the following is true?
1) The one opposite Arun uses 2 sachets of sugar less than him.
2) The one opposite Raman eats 3 cookies more than him.
3) The one opposite Joe uses 1 sachet of sugar more than him.
4) The one opposite Sam eats 5 cookies.

3. Which of the following is false?
1) Arun sits next to someone who uses same number of sachets as him.
2) Joe sits next to someone who eats the same number of cookies as him.
3) Raman sits next to someone who uses same number of sachets as him.
4) Sam sits next to someone who eats the same number of cookies as him.


Questions 4 to 7:

Eight members of a trekking club - A, B, C, D, E, F, G and H – plan to go trekking this weekend. Two simultaneous treks – Trek I and Trek II - are planned, each of which will have exactly 4 participants. A, C and G are doctors. A, B, E and H have prior trekking experience. It is decided that each group should have at least 1 doctor and 2 members with prior experience. Also B and C must be in different groups.

4. If D and F insist in going on Trek II, which of the following must also go on Trek II?
1) G
2) E
3) B
4) H


5. If F and C go on Trek II, then in how many ways can the group for Trek I be formed?
1) 1 way
2) 2 ways
3) 3 ways
4) No such group possible


6. If A is the only doctor in his group, then which of the following is necessarily true?
1) B and G go on the same trek.
2) E and G go on different treks.
3) D and F go on the same trek.
4) D and F go on different treks.



7. If A and B go on different treks, which of the following could be true?
1) A and G go on the same trek.
2) D and F go on the same trek.
3) E and H go on the same trek.
4) F and H go on the same trek.



Answers & Solutions:

Question 1 to 3:


  1. 3
  2. 2
  3. 3



We first make an elementary table:


Number of cookies with Sam must be m or 2m. But if it is 2m then we get 7m + 3 = 18 which is not possible. So, Sam has m cookies with m = 3 (5m + 3 = 18). Also, Raman adds milk so he cannot be opposite to Sam. And since Raman has more sugar than Arun, 2y > 2x. The only possibility then is x = 1, 2x = y = 2, 2y = 4. We thus get the complete table:




4. Neither D nor F have prior experience, and neither is a doctor. So the only way to fulfil the given conditions is if A, who also has prior experience, goes as the doctor, while the 4th member also has prior experience. Thus the other doctors, C and G, must go on Trek I, and B must be on Trek II. Hence (3).

5. If F and C go on Trek II, B must go on Trek I. Trek II requires the remaining 2 people to have prior experience and hence D and G also must go on Trek I. Now, any one of the three remaining people with prior experience (A, E and H) can be sent on Trek I and the other two on Trek II. Hence 3 ways. Hence (3).

6. If A is the only doctor in his group, C and G must be in the other group. Thus B must be in the first group. Also, the other two with C and G must be having prior experience. Thus they must be E and H, while D and F must go with A and B. Hence (3).


7. Since both A and C cannot go with B, they must be together. Hence the remaining doctor, G, must go with B. Also, each group has only one experienced person so far, and hence E and H must go to different groups. Similarly the fourth spot in each group must be taken by D and F, one to each group. Hence the options (1), (2) and (3) are all impossible, but option (4) could take place (for example Trek I - A, C, D, E and Trek II - B, F, G, H is a possible combination). Hence,(4).







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