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**exampundit**. Here is set on Time, Work and Wages with detailed solutions on the chapterwise Quantitative Aptitude Word problems for the upcoming SBI PO Prelims 2017.

1. A single petrol tank supplies
the petrol to the Lucknow, while the tank is fed by a single pipeline filling
the tank with the stream of uniform volume. When the tank is full and if 40,000
liters of petrol is used daily, the supply fails in 90 days. If 32,000 liters
of petrol is used daily, it fails in 60 days. How much petrol can be used daily
without interruption ?

A) 66000

B) 76000

C) 56000

D) 50000

E) 45000

2. Four pipes A,B, C and D can
fill a cistern in 20,25, 40 and 50 hours
respectively. The first pipe A was opened at 6:00 am, B at 8:00 am, C at 9:00
am and D at 10:00 am. When will the Cistern be full?

A) 2.09pm

B) 3.09pm

C) 4.09pm

D) 5.00pm

E) 4.00pm

3. Pipe A can fill the petrol
reservoir in 4 hours, while pipe B can fill it in 6 hours working separately. Pipe
C can empty whole the reservoir in 4 hours. Rahul opened the pipe A and B
simultaneously to fill the empty reservoir. He wanted to adjust his alarm so
that he could open the pipe C when it was half-filled, but he mistakenly
adjusted his alarm at a time when his reservoir would be 3/4th filled. What is
the time difference between both the cases, to fill the reservoir fully:

A) 54 minutes

B) 32 minutes

C) 20 minutes

D) 15 minutes

E) None

4. Krishna can reap a field in 20
days, while ram can reap the field in 25 days. They started to reap the field
together. Few days later Sudama also joined them and thus all of them completed
the whole work in 10 days. All of them were paid total Rs.800. What is the
Share of Sudama?

A) 70

B) 80

C) 90

D) 100

E) None

5. Pipe 1 can fill a tank in 12
hours and pipe 2 can fill in 15 hours, separately. A third pipe 3 can empty in
20 hours. Initially pipe 1 was opened, after one hour pipe 2 was opened and then after 1 hour of opening of pipe2 , pipe 3 was opened. In how many hours
tank will fill?

A) 9 2/3 hours

B) 10 hours

C) 6 2/3 hours

D) 5 hours

E) None

6. A group of boys decided to do
a piece of work in 4 days. But since,
20 boys dropped out everyday, the job completed at the end of 7th day. How many
boys were there at the beginning?

A) 240

B) 140

C) 150

D) 280

E) 400

7. After passing out from a
reputed fashion designing academy 5 friends A,B,C,D and E open a fashion store
of their own. If 5 of them can design 1800 dresses in 90 days working alternatively,
find the minimum possible number of dresses they can design in a single day by
working together?

A) 100

B) 20

C) 50

D) 4

E) None

8. In how many days can the work be done by 8 men and 12 women?

i. 6 men and 5 women can do the
work in 6 days

ii. 3 men and 4 women can do the
work in 16 days

iii. 18 men and 15 women can do
the work in 5 days.

Which of the statements I, ii, iii
are required to answer the above question?

A) 2 only

B) All the three

C) Any one of the 3

D) Any 2 of the 3

E) None

__Answers:__- Ans-c
- Ans-b
- Ans-a
- Ans-b
- Ans-a
- Ans-b
- Ans-a
- Ans-d

__Detailed Solutions:__
1. Let x liter be the per day filling and v liter be the
capacity of the tank, then

90x + v = 40000 × 90
----- (1)

60x + v= 32000 × 60
------ (2)

Solving eq. (1) and (2), we get

x = 56000

Hence 56000 ltrs can be supplied everyday without
interruption.

2. Efficiency of P= 5%

Efficiency of Q= 4%

Efficiency of R= 2.5%

Efficiency of S= 2%

%

Thus, at 10 am pipe P,Q and R filled 30.5% of the cistern.

Now, the time taken by P,Q,R and S together to fill the
remaining capacity of the cistern

=69.5/13.5=139/27=5 Hours and 9 minutes(approx)

Therefore, total time =4 hrs + 5hrs 9 mins

= 9 hrs and 9 mins

It means cistern will be filled up at 3:09 pm

3. In ideal Case:

Time taken to fill the reservoir half by A and B =
50/41.66=6/5 hours

Time taken by A,B and C to fill rest half of the
reservoir=50/16.66 = 3 hours

Total time = 6/5 +3=
4 hours 12 min

In second case:

Time taken to fill 3/4 reservoir by A and B =75/41.66=9/5
hours

Time taken by A,B and C to fill rest 1/4 reservoir =
25/16.66=3/2 hours

Total time =9/5 + 3/2=
18+15/10 =3 hours 18 min

Therefore , difference in time = 54 minutes

4. Efficiency of krishna = 100/20=5%

Efficiency of ram = 100/25=4%

Thus, in 10 days working together they will complete only
90% of the work.

[(5+4)×10] =90%

Hence, the remaining work will surely done by sudama, which
is 10%.

Thus, sudama will get 10% of Rs. 800, which is Rs.80

5. Pipe 1 eff= 8.33%

Pipe2=6.67%

Pipe3=5%

When pipe 3 was open, pipe 1 filled 16.66% capacity

Wen pipe 3 opened, pipe 2 filled 6.67% capacity

Therefore rest capcity filled by pipe3= 100-23.34=76.67%

Net eff of pipe 1, 2 and 3 = 10%

Hence 3 pipes will take= 76.66/10=7.66=7 2/3 hrs

Total = 2 hrs= 7 2 /3 hrs= 9
2/3 hours

6. Solve through options-
lhs 140 x 4=
140+120+100+…+20)=560= rhs

7. Let A,B,C,D,E design a, b, c, d, e dresses per day
respectively

1/a+1/b+1/c+1/d+1/e=90/1800=1/20

When a=b=c=d=e we get min value 5×1/a=1/20=>a+b+c+d+e=100

8. Any of the 2 statements will give 2 equation in x and y
which can be solved simultaneously. For example I and ii give 6x+5y=1/6

And 3x+4y=1/16

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