*Hello and welcome to*

**exampundit**. Here is a set of Reasoning Quiz for upcoming Bank and Insurance Exams.

**Directions(Q. 1-6):**Study the following information and answer the Questions given below it:

A blacksmith has five iron articles A, B, C, D and E, each having a different weight.

(i) A weighs twice as much as B.

(ii) B weighs four and a half times as much as C.

(iii) C weighs half as much as D.

(iv) D weighs half as much as E.

(v) E weighs less than A but more than C

1. Which of the following is the lightest in weight ?

A) A

B) B

C) C

D) D

E) E

2. E is lighter in weight than which of the other two
articles?

A) A, B

B) D, C

C) A, C

D) D, B

E) B, E

3. E is heavier than which of the following two articles ?

A) D, B

B) D, C

C) A, C

D) A, B

E) None of these

4. Which of the following articles is the heaviest in weight
?

A) A

B) B

C) C

D) D

E) E

5. Which of the following represents the descending order of
weights of the articles?

A) A, B, E, D, C

B) B, D, E, A, C

C) E, C, D, A, B

D) C, A, D, B, E

E) A, B, D, E, C

6. Which of the above given statements is not necessary to
determine the Correct order of articles according to their weights?

A) 1

B) 2

C) 3

D) 4

E) 5

**Directions (Q. 7-11):**In the following questions, the symbols @, $, %, # and © are used with the following meanings illustrated—

˜A @ B™ means ˜A is not smaller than B™.

˜A $ B™ means ˜A is not greater than B™.

˜A % B™ means ˜A is neither smaller than nor equal to B™.

˜A # B™ means A is neither greater than nor equal to B™.

A © B™ means ˜A is neither smaller than nor greater than B™.

In each of the following questions assuming the given
statements to be true, find out which of the two conclusions I and II given
below them is/are definitely true.

7.

**Statements:**
A @B,

B%D,

D©K

**Conclusions:**

I. A©K

II. B%K

A) If only conclusion I is true.

B) If only conclusion II is true.

C) If either conclusion I or conclusion II is true.

D) If neither conclusion I nor conclusion II is true.

E) If both conclusions I and II are true.

8.

**Statements:**
M $ N,

N @ R,

T % R

**Conclusions:**

I. M @ R

II. T©R

A) If only conclusion I is true.

B) If only conclusion II is true.

C) If either conclusion I or conclusion II is true.

D) If neither conclusion I nor conclusion II is true.

E) If both conclusions I and II are true.

9.

**Statements:**
J % K,

J # M,

M@ N

**Conclusions:**

I. M % J

II. K % N

A) If only conclusion I is true.

B) If only conclusion II is true.

C) If either conclusion I or conclusion II is true.

D) If neither conclusion I nor conclusion II is true.

E) If both conclusions I and II are true.

10.

**Statements:**
J # K,

K©L,

P$L

**Conclusions**:

I. P$K

II. J#L

A) If only conclusion I is true.

B) If only conclusion II is true.

C) If either conclusion I or conclusion II is true.

D) If neither conclusion I nor conclusion II is true.

E) If both conclusions I and II are true.

11.

**Statements:**
A @ B,

B # C,

D $ E

**Conclusions:**

I. C © A

II. C % A

A) If only conclusion I is true.

B) If only conclusion II is true.

C) If either conclusion I or conclusion II is true.

D) If neither conclusion I nor conclusion II is true.

E) If both conclusions I and II are true.

- Ans. C
- Ans. A
- Ans. B
- Ans. A
- Ans. A
- Ans. E
- Ans. B
- Ans. D
- Ans. A
- Ans. E
- Ans. D

Detailed Solutions:

1. Sol.

Let the weight of E be x kg

weight of A =2.25 x kg

weight of B =1.125 x kg

weight of C =0.25 x kg

weight of D =0.5 x kg

weight of E = x kg

Now the increasing order of weights is,

C < D < E < B < A

Lightest in weight = C

2. Sol. Let the weight of E be x kg

weight of A =2.25 x kg

weight of B =1.125 x kg

weight of C =0.25 x kg

weight of D =0.5 x kg

weight of E = x kg

Now the increasing order of weights is,

C < D < E < B < A

E is lighter than A,B

3. Sol. Let the weight of E be x kg

weight of A =2.25 x kg

weight of B =1.125 x kg

weight of C =0.25 x kg

weight of D =0.5 x kg

weight of E = x kg

Now the increasing order of weights is,

C < D < E < B < A

E is heavier than C, D

4. Sol. (i) A weighs 2 B

(ii) B weighs 4.5 C

(iii) C weighs 0.5 D

(iv) D weighs 0.5 E

(v) A > E > C

D weights 0.5 E and B weights 4.5 (0.5D) ---> 2.25 D
----> Therefore , B > D

Also B > E because B weights 2.25 (0.5E) ----> 1.125 E

Now concluding all the five statements A > B > E >
D > C<d<e<b

</d<e<b

5. Sol. Let the weight of E be x kg weight of A =2.25 x kg

weight of B =1.125 x kg

weight of C =0.25 x kg

weight of D =0.5 x kg

weight of E = x kg

Now the increasing order of weights is,

C < D < E < B < A

Decreasing order of weights is A > B > E > D > C

**6.**Sol. Let the weight of E be x kg weight of A =2.25 x kg

weight of B =1.125 x kg

weight of C =0.25 x kg

weight of D =0.5 x kg

weight of E = x kg

Now the increasing order of weights is,

C < D < E < B < A

(v) statement is not required

**7.**Sol. Statements: A

__>__B > D = K

Conclusion:

I. A = K false

II. B > K True

I. A = K false

II. B > K True

**8.**Sol. Statements: M

__<__N

__>__R < T

Conclusions:

I. M

II. T = R False

I. M

__>__R FalseII. T = R False

**9.**Sol. Statements: K < J < M

__>__N

Conclusions:

I. M > J True

II. K > N False

I. M > J True

II. K > N False

**10.**Sol. Statements: J < K = L

__>__P

Conclusions:

I. P

II. J < L True

I. P

__<__K TrueII. J < L True

**11.**Sol. Statements: A

__>__B < C, D

__<__E

Conclusions:

I. C = A False

II. C > A False

I. C = A False

II. C > A False

Sponsored

Regards

**Team ExamPundit**

## 0 comments